3.12.58 \(\int \frac {(1-2 x)^2}{(2+3 x) (3+5 x)} \, dx\)

Optimal. Leaf size=26 \[ \frac {4 x}{15}-\frac {49}{9} \log (3 x+2)+\frac {121}{25} \log (5 x+3) \]

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Rubi [A]  time = 0.01, antiderivative size = 26, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {72} \begin {gather*} \frac {4 x}{15}-\frac {49}{9} \log (3 x+2)+\frac {121}{25} \log (5 x+3) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 - 2*x)^2/((2 + 3*x)*(3 + 5*x)),x]

[Out]

(4*x)/15 - (49*Log[2 + 3*x])/9 + (121*Log[3 + 5*x])/25

Rule 72

Int[((e_.) + (f_.)*(x_))^(p_.)/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :> Int[ExpandIntegrand[(
e + f*x)^p/((a + b*x)*(c + d*x)), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && IntegerQ[p]

Rubi steps

\begin {align*} \int \frac {(1-2 x)^2}{(2+3 x) (3+5 x)} \, dx &=\int \left (\frac {4}{15}-\frac {49}{3 (2+3 x)}+\frac {121}{5 (3+5 x)}\right ) \, dx\\ &=\frac {4 x}{15}-\frac {49}{9} \log (2+3 x)+\frac {121}{25} \log (3+5 x)\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 27, normalized size = 1.04 \begin {gather*} \frac {1}{225} (60 x-1225 \log (3 x+2)+1089 \log (-3 (5 x+3))+40) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 - 2*x)^2/((2 + 3*x)*(3 + 5*x)),x]

[Out]

(40 + 60*x - 1225*Log[2 + 3*x] + 1089*Log[-3*(3 + 5*x)])/225

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(1-2 x)^2}{(2+3 x) (3+5 x)} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(1 - 2*x)^2/((2 + 3*x)*(3 + 5*x)),x]

[Out]

IntegrateAlgebraic[(1 - 2*x)^2/((2 + 3*x)*(3 + 5*x)), x]

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fricas [A]  time = 1.50, size = 20, normalized size = 0.77 \begin {gather*} \frac {4}{15} \, x + \frac {121}{25} \, \log \left (5 \, x + 3\right ) - \frac {49}{9} \, \log \left (3 \, x + 2\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^2/(2+3*x)/(3+5*x),x, algorithm="fricas")

[Out]

4/15*x + 121/25*log(5*x + 3) - 49/9*log(3*x + 2)

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giac [A]  time = 0.93, size = 22, normalized size = 0.85 \begin {gather*} \frac {4}{15} \, x + \frac {121}{25} \, \log \left ({\left | 5 \, x + 3 \right |}\right ) - \frac {49}{9} \, \log \left ({\left | 3 \, x + 2 \right |}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^2/(2+3*x)/(3+5*x),x, algorithm="giac")

[Out]

4/15*x + 121/25*log(abs(5*x + 3)) - 49/9*log(abs(3*x + 2))

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maple [A]  time = 0.01, size = 21, normalized size = 0.81 \begin {gather*} \frac {4 x}{15}-\frac {49 \ln \left (3 x +2\right )}{9}+\frac {121 \ln \left (5 x +3\right )}{25} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-2*x)^2/(3*x+2)/(5*x+3),x)

[Out]

4/15*x-49/9*ln(3*x+2)+121/25*ln(5*x+3)

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maxima [A]  time = 0.53, size = 20, normalized size = 0.77 \begin {gather*} \frac {4}{15} \, x + \frac {121}{25} \, \log \left (5 \, x + 3\right ) - \frac {49}{9} \, \log \left (3 \, x + 2\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^2/(2+3*x)/(3+5*x),x, algorithm="maxima")

[Out]

4/15*x + 121/25*log(5*x + 3) - 49/9*log(3*x + 2)

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mupad [B]  time = 0.04, size = 16, normalized size = 0.62 \begin {gather*} \frac {4\,x}{15}-\frac {49\,\ln \left (x+\frac {2}{3}\right )}{9}+\frac {121\,\ln \left (x+\frac {3}{5}\right )}{25} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*x - 1)^2/((3*x + 2)*(5*x + 3)),x)

[Out]

(4*x)/15 - (49*log(x + 2/3))/9 + (121*log(x + 3/5))/25

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sympy [A]  time = 0.12, size = 24, normalized size = 0.92 \begin {gather*} \frac {4 x}{15} + \frac {121 \log {\left (x + \frac {3}{5} \right )}}{25} - \frac {49 \log {\left (x + \frac {2}{3} \right )}}{9} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**2/(2+3*x)/(3+5*x),x)

[Out]

4*x/15 + 121*log(x + 3/5)/25 - 49*log(x + 2/3)/9

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